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Final Exam Review Fall 2006: Handling an address book

Post your questions here:

def contact(wfind):
  addressbook=getMediaPath("addresses.txt")
  addresses=open(addressbook,"rt")
  addresstext=addresses.read()
  addresses.close()
  afound=addresstext.find(wfind)
  if afound==-1:
    print "Not Found"
  if afound!=-1:
    aend=addresstext.rfind(":",0,afound)
    astart=addresstext.rfind("#",0,afound)+1
    address=addresstext[astart:aend]
    print address


is this right? Jeffrey Geisert
This is what I get:
def contact (keyword):
  file=open(getMediaPath("contacts.txt"), "rt")
  address=file.read()
  file.close()
  lines = address.split ("\n")
  
  for i in lines:
    if i.find(keyword)!=-1:
      contactend=i.rfind(":")
      contactstart=i.rfind ("#")
      print i[contactstart+1:contactend]
    if i.find(keyword)==-1:
      print "not found"

def contact(keyword):
file = file.open("contacts.txt","rt")
contacts = file.read()
file.close()
contacts.find(keyword)
if contacts !== -1:
begin = contacts.rfind("#", contacts)
end = contacts.rfind(":", contants)
print "contacts[begin:end]"
if contacts == -1:
print "Not Found"

would this work?
Not without indentions. -Brittany Duncan
def contact(keyword):
  file=getMediaPath("contacts.txt")
  file = open(file,"rt")
  contacts = file.read()
  file.close()
  k=contacts.find(keyword)
  if k != -1:
    begin = contacts.rfind("#",0,k)
    end = contacts.rfind(":",0,k)
    print contacts[begin+1:end]
  else:
    print "Not Found"

Jeffrey Wells


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