Summer2006 Midterm 1 Review: Generalized image filter
Questions?
def changeRGB(picture, red, green, blue):
for p in getPixels(picture):
red = getRed(p)
green = getGreen(p)
blue = getBlue(p)
setRed (p, red*-.75)
setGreen (p, green*.25)
setBlue (p, blue-.25)
| Close but not quite. Math Problem: How do I calculate 75% of 50? -Albert d'Heurle |
Shouldn't this be another generalized function like the one before, without hard coding the percentages into the program?
| Yes, the numbers shouldn't be hardcoded. That would make the above function incorrect. - Bobby Mathew |
def changeRGB(picture, red, green, blue):
for p in getPixels(picture):
red = getRed(p)
green = getGreen(p)
blue = getBlue(p)
setRed (p, red*.75)
setGreen (p, green*1.25)
setBlue (p, blue*.25)
| Read the above post. You shouldn't be having the numbers like .75, 1.25 etc. Use the parameters instead of the actual numbers. - Bobby Mathew |
Would this work?
def changeRGB(picture, red, green, blue):
for p in getPixels (picture):
red = getRed(p)
green = getGreen(p)
blue = getBlue(p)
setRed = (p, red - (red.75))
setGreen = (p, green + (green.25))
setBlue = (p, blue - (blue.25))
so the last answer should be correct, but instead of each percentage do you want us to write 'amount'?
| The parameters 'red', 'green' and 'blue' represent the amount for each value so you wouldn't actually need to use amount as a seperate variable. -Bobby Mathew |
def changeRGB(picture, redamount, greenamount, blueamount)
for p in getPixels(picture):
red = getRed(p)
green = getGreen(p)
blue = getBlue(p)
setRed = (p, red*(1+redamount))
setGreen = (p, green*(1+blueamount))
setBlue = (p, blue*(1+greenamount))
no its not, he forgot his colon :)
| Good eye, I'm mainly checking if the actual calculation steps are right. - Bobby Mathew |
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