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| Absolute value of 50 minus whatever the frame value is. -Student1680 |
| I'm not sure what you mean by this. -Student1680 |
| Yes and yes. -Student1680 |
| That's how I would recommend doing this. Plug in 0. Plug in 50. Plug in 100. Connect the dots. -Student1680 |
| Yes. -Student1680 |
| These should be in the book. On the test, we won't ask you anything that was never shown in class like abs. And if we did, we'd explain it in the problem instructions. -Student1680 |
| "If the frame number is just one digit..." -Student1680 |
| You are concatenating all the strings to form a full path and filename. -Student1680 |
| My suggestion is to disregard the actual width and height values and merely think of them in terms of width and height. For example, on frame 50, the x value is 50 * width / 100. If you plug in 640 for width you get some number that doesn't tell you much. But if you leave it in terms of width you can simplify that to width / 2. This means that 50 frames into the movie the tickertape is exactly half way across the picture horizontally. Same reasoning should be applied to the y coordinate. -Student1680 |
| In addition to my above explaination, if you're adding the frame number to a coordinate it's moving away from that axis. If you're subtracting the frame number, it's moving towards it. But be careful, as absolute value tends to switch directions at some point. -Student1680 |
| A directory is a folder path and it looks different for different computers (PC C:\blah\blah\blah\ vs. Mac /Users/me/blah/blah/blah/. If we ask you what the filename looks like, you can assume we're excluding the directory name. -Student1680 |
| See various above statements. -Student1680 |
| Frame is a number that goes from 0 to 99. I'm not sure what you mean by frame38. -Student1680 |
| The string is whatever you want the ticker tape to say. -REMOVED O'Hare |
| REMOVEDngth of the string. REMOVEDw many characters are in it. In this case, how many digits the number is. -Student1680 |
| You know that the top left corner of the image is 0,0. So plot the (x,y) for when frame = 0. Then plot the (x,y) for 50, then 100 (close enough to 99). Draw a box and plot the dots. If x=width / 2 and y = 0, then that would be located at the midpoint of the top of the box. -Student1680 |
| Bingo. -Student1680 |
| Yes, but on the test, simply frame01.jpg will suffice. -Student1680 |
| That's a very good question. I have no idea. Just ignore one. -Student1680 |
| The review session will be Monday from 7 to 10 PM in Room 16 in the College of Computing. -Student1206 |