Midterm Exam 1 Review Fall 2004: If red were green were red
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def redGreenOut():
file = pickAFile()
pic = makePicture(file)
show(pic)
for x in getPixels(pic):
r = getRed(x)
b = getBlue(x)
g = getGreen(x)
n = (r+g)/2
q = makeColor(n,b,n)
setColor(x,q)
repaint(pic)
show(pic)
is that better?
| Albert, try posting the code as in the FAQ so that we can figure out which is code and which are statements. From what's here, I can see that you're not actually answering the question correctly. (Hint: Consider inputs.) Mark Guzdial |
| Also, are we using a RGB or an RBG color scheme?? Kelly Lyons |
If you averaged out the red and green pixels for an image wouldn't you be left with a blue/grey/yellow picture?
| Try it and tell us. Better yet, post your result and show us. Mark Guzdial |
| Try doing it in JES to different pictures and see. Kelly Lyons |
def redGreenOut(pic):
for px in getPixels(pic):
red=getRed(px)
green=getGreen(px)
mix=(red+green)/2
newcolor=setColor(px, makeColor(mix,mix,blue))
yeah...i think this one is better:
def redGreenOut(pic):
for px in getPixels(pic):
red=getRed(px)
green=getGreen(px)
blue=getBlue(px)
mix=(red+green)/2
newcolor=setColor(px, makeColor(mix,mix,blue))
| Looks pretty good, but why are you creating the variable newcolor in the last line. True, it does not cause an error, but do you really need it? Kelly Lyons |
def redGreenOut(pic):
for px in getPixels(pic):
r=getRed(px)
b=getBlue(px)
g=getGreen(px)
rg=(r+g)/2
color=makeColor(rg,b,rg)
setColor(px,color)
show(pic)
I just remembered that the color order is rgb. That means that color=makeColor aught to be (rg,rg,b) instead of (rg,b,rg) right?
def redGreenOut(pic):
for p in getPixels(pic):
r = getRed(p)
g = getGreen(p)
b = getBlue(p)
x = (r+g)/2
colorBlind = makeColor(x,x,b)
setColor(p, colorBlind)
show(pic)
def redGreenOut2(pig):
pigf=getMediaPath("pig.jpg")
pig=makePicture(pigf)
for p in getPixels(pig):
newRed = getRed(p)
newGreen = getRed(p)
newBlue = getBlue(p)
luminance = (newRed+newGreen)/2
setColor(p,makeColor(luminance,luminance,newBlue))
show(pig)
| Your function takes input, i.e. a picture, so why are you making a picture inside the function (on your first two lines) Kelly Lyons |
def redGreenOut(picture):
for px in getPixels(picture):
red = getRed(px)
green = getGreen(px)
setRed(px, (red+green)/2)
setGreen(px, (red+green)/2)
show(picture)
ok - i now know that i cant use red and green as variables - change those to r and g instead
how do i post my picture to see if i am writing the program correctly? thanks.
does this picture look right? 
def redGreenOut(picture):
for px in getPixels(picture):
r = getRed(px)
g = getGreen(px)
colorBlind = (r+g)/2
setRed(px, colorBlind)
setGreen(px, colorBlind)
Stephanie Chester
My code looks like this. Am I doing something wrong?
It works alright.
def redGreenOut(picture):
for p in getPixels(picture):
average=(getRed(p)+getGreen(p))/2
blue=getBlue(p)
setColor(p,makeColor(average,average,blue))
QUESTION: if you have some process(x, y) with x and y being whatever, like values or colors, does it take the original x and make it what you defined y as?
| It depends what process you are talking about. But, for instance, in the case of setColor(x, y), x will be the original pixel value, and then y is the new value that you will be changing x to. Summer McWilliams |
| It depends on what your process(x,y) did inside it's function. It won't automatically make the x = y unless somewhere in the code, you had a line that said x = y, and then for the remainder of the function x would be equal to y. Does this answer your question, or I am completely missing what you're getting at? Kelly Lyons |
def redGreenOut():
file=pickAFile()
pic=makePicture(file)
for px in getPixels(pic):
r=getRed(px)
g=getGreen(px)
b=getBlue(px)
rg=(r+g)/2
color=makeColor(rg,rg,b)
setColor(px,color)
show(pic)
Is this right?
| No, your function is supposed to be taking input Kelly Lyons |
Is it right?
def redGreenOut():
picture = makePicture(pickAFile())
for px in getPixels(picture):
r=getRed(px)
g=getGreen(px)
b=getBlue(px)
average=(r+g)/2
setColor(px, makeColor(average, average, b))
show(picture)
| Your function is supposed to be taking input, not creating the picture inside the function Kelly Lyons |
def redGreenOut():
file=pickAFile()
picture=makePicture(file)
show(picture)
for p in getPixels(picture):
r=getRed(p)
g=getGreen(p)
setRed(p,((r+g)/2))
setGreen(p,((r+g)/2))
repaint(picture)
| Your function is supposed to take input, not create a picture inside your function Kelly Lyons |
When do you know when you need to show the picture in the answer?
| When the specifications say for the function to show the picture Kelly Lyons |
Guys, check this out–
def redGreenOut(pic):
for pixels in getPixels(pic):
r=getRed(pixels)
g=getGreen(pixels)
newColor=(r + g) / 2
setRed(pixels, newColor)
setGreen(pixels, newColor)
I do not know if there is anything wrong with this answer. However, I do wanna know whether one has to have r, g, and b all included everytime he or she codes for a picture because this answer does not have the blue value included in it, which I don't think I ever need to include the blue in it.
| Yes, you are right. You never have to use the blue value at all in writing the code the way your wrote it. Kelly Lyons |
Oops, I am sorry, I did the indentation wrong. Somebody please try to fix it, thanx!
Do you have to include repaint() in the function?
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